What is the output of the following code?
int arr[] = {1, 2, 3, 4, 5};
int* ptr = arr;
cout << *(ptr + 2) << endl;

Question

What is the output of the following code?int arr[] = {1, 2, 3, 4, 5};int* ptr = arr;cout << *(ptr + 2) << endl;a)1b)2c)3d)4Correct answer is option 'C'. Can you explain this answer?

Answer

'ptr' is a pointer to the first element of the array 'arr'. When we add an integer value to a pointer, it moves the pointer forward by that many elements. So, 'ptr + 2' points to the third element of the array. The expression '*(ptr + 2)' dereferences the pointer and gives the value at that memory location, which is 3.

Answer

The code you provided is incomplete. The statement `cout` is not complete, so it will result in a compilation error. In order to provide the expected output, you need to complete the statement `cout` by specifying what you want to output.

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